$\lim_{x\to\infty}\left(\frac{3x-7}{x+4}\right)$
$-2x^2+8x^2-3x+2x^2$
$y=-16x^{2}+4x+5$
$\cos\left(x\right)=\frac{1}{7}$
$5000+-1200$
$\cos^2+\cos^2\sin^2=\cos2$
$\frac{\cos\left(x\right)+\sin\left(x\right)}{\sin\left(x\right)-\cos\left(x\right)}=\frac{-\cos\left(2x\right)}{1-\sin\left(2x\right)}$
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