$5x+1=2x-5$
$\frac{x}{2-4x}-\frac{5}{6}\le0$
$\frac{-3}{x-2}+\frac{4}{x-3}$
$\left(1+\tan^2x\right)^3$
$4m^3n^2-2m^2n-5m^3n^2+2m^2n$
$\left(mn+1\right)\left(mn-1\right)$
$m^3+10m^2+2m-13$
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