$\frac{dy}{dx}=\frac{3y}{2x}$

$3\sin\left(x\right)-2=1$

$3.6^3$

$\left(x-y\right)^2\frac{dy}{dx}=4$

$\int\frac{y^6}{2}dx$

$-0.75+\left|\left(\frac{\sqrt{16}}{\sqrt{25}}\right)-0.2\right|+\frac{2}{3}\cdot\left(\frac{1}{4}\right)^2$

$\int\frac{2x-1}{\left(x-1\right)\left(x^2-2x+1\right)}dx$