$\cos\left(x\right)\sec\left(x\right)-\sin^2\left(x\right)=\cos^2\left(x\right)x$
$\left(f^2m^2\right)\left(f^3m\right)$
$3x-6x^2+9^3$
$\frac{6x^2+5x^3-1}{3x^2+x-2}$
$\int\left(\frac{x+5}{x^2+10x+30}\right)dx$
$5.5+0.3$
$-33.42\:-\left(-110.02\right)$
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