$\left(1-\frac{3}{x}\right)^{2x}$
$x^2-6x+2=0$
$-1=\sin\left(x\right)$
$\int\left(3x^2+4\right)^2dx$
$\left(x+y+z\right)\left(x+y\right)$
$9\left(x^2+36x\right)$
$\frac{1}{\left(s+6\right)\left(s-4\right)}+\frac{2}{s+6}$
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