$\frac{dy}{dx}=6y-3y^2$
$\frac{dy}{dx}=\frac{5\cdot\:sin\left(y\right)}{x\cdot tan\:y}$
$-8x^2+x^2$
$\frac{dy}{dx}=\frac{y^2}{2x}$
$\sin4x\cos4x$
$\frac{2x^{-1}+x^{-2}}{1-3x^{-1}+2x^{-2}}$
$3x^2+147=0$
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