Exercise
$\frac{\left(\:15\right)}{2u^3+6u}+\frac{\left(6\right)}{u^2+3}-\frac{\left(5\right)}{2u}$
Limit of this function
$\lim_{w\to0}\left(\frac{15}{2u^3+6u}+\frac{6}{u^2+3}+\frac{-5}{2u}\right)=\frac{15}{2u^3+6u}+\frac{6}{u^2+3}+\frac{-5}{2u}$
See step-by-step solution
Derivative of this function
$\frac{d}{du}\left(\frac{15}{2u^3+6u}+\frac{6}{u^2+3}+\frac{-5}{2u}\right)=\frac{-15\left(6u^{2}+6\right)}{\left(2u^3+6u\right)^2}+\frac{-12u}{\left(u^2+3\right)^2}+\frac{5}{2u^2}$
See step-by-step solution
Integral of this function
$\int\left(\frac{15}{2u^3+6u}+\frac{6}{u^2+3}+\frac{-5}{2u}\right)du=\frac{12u-5u^2}{2\left(u^2+3\right)}+C_0$
See step-by-step solution