$\frac{3dy}{dx}=\sin\left(4x+2\right)$

$\int\:\cos^3\left(2x\right)\sin^5\left(2x\right)dx$

$\left(\frac{2}{3}x+2\right)\left(\frac{1}{5}x-1\right)$

$\frac{dy}{dx}\:y=\tan^{-1}\left(\sqrt{x}\right)$

$-42-\left(-16\right)+9$

$\left(u-1\right)\left(u-3\right)\left(9u+3\right)$

$m^2-16n^2$