$\frac { \int d x } { x }$
$\left(6x+3xy\right)^2$
$\int\frac{2x+1}{\left(x+3\right)^2\left(x+2\right)\left(x+5\right)}dx$
$3x-2y+z=8$
$\frac{tan^2\left(x\right)}{\sin^2\left(x\right)}$
$2x^3-2x^3+3x^2+5x-4x-3$
$\sqrt[5]{15a^2.\sqrt[5]{32a^3}}$
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