$\frac{5x-4}{-5}$
$\left(2x\:+\:9\right)\:\left(2x\:+\:1\right)$
$\left(-2x-3\right)^3$
$-5\cdot5x^2$
$resolver\:\frac{\sqrt[3]{3x^4}}{\sqrt[9]{273x^2}}$
$6x^2-3y^2=1$
$\left(a^3x+by^3\right)^2$
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