$\frac{\left(7^3\right)^2}{7^2}$
$\lim_{x\to\infty\:}\left(\frac{x+1}{x}\right)^{3x}$
$3x-13=14$
$13-\left|6-\left(8-5\right)+\left(3-11\right)\right|$
$x^2+x+81$
$\left(3x^4-10\right)\left(3x^4+10\right)$
$\sqrt{-121}$
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