$3\left(x+2\right)\left(x-2\right)$
$\frac{4x^2-9m^2n^4}{2x+3mn^2}$
$-3\left(-\frac{4}{3}\right)$
$12x^2\left(x-3\right)$
$-2x+\frac{4}{5}\le0.5x-2.2$
$\left(-3x^3\right)\left(6x^4\right)$
$-14.000-12.600+31.500+22.600$
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