$8ab^3\:+\:8a^3b$
$\sec\left(x\right)\cdot\sec\left(x\right)-1=\frac{1}{4}$
$a^2+a^2-2a^2$
$\frac{d}{dx}\frac{8}{3-x}$
$2\sqrt{4}+3\sqrt{16}$
$\sqrt[6]{2x}$
$3\left(1\right)^4+5\left(1\right)^3+25\left(1\right)^2+45\left(1\right)-18$
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