$81b^4c^6-49m^6n^2$
$\tan\left(x\right)^3-3\tan\left(x\right)=0$
$\int\:\frac{4-x^3}{e^x}\:dx$
$x^2+6x-1\le\:3x^2+3x-6$
$-3x+8<15$
$\left(-3a+1\right)^3$
$8^{8}-100x^{4}+8$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!