$\left(x^{\frac{1}{2}}+x^{\frac{1}{4}}-1\right)^3$
$\frac{dy}{dx}+y^{2\:}-y=0$
$\frac{d}{dx}-2x^4+x^2y^5-y^{\frac{1}{2}}=x+1$
$\frac{3y^2-4y+5}{6\sqrt{y}}$
$\left(2x-6\right)\left(x-3\right)$
$\sqrt{13\left(9\right)}$
$\left(2x+1-\left(6x+6\right)\right)^2$
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