$\frac{\left(2d\right)^3}{2d^5}$
$3\cdot\left(12-19\right)+5\left(-18+16\right)-\left(-4\right)\left(-5\right)$
$3\left(\frac{1}{2}m\right)^2\left(\frac{3}{5}n\right)$
$7^{0+1}$
$\lim_{x\to-1}\left(\frac{5x+4}{7x+6}\right)^{\frac{1}{2\left(x+1\right)}}$
$3y^{\left(1-2\right)}$
$-10y+6y=28$
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