$x^2\frac{dy}{dx}+\left(2xy+2x^2+y^2\right)=0$
$x^2-6x-41=0$
$\left(+3\right)-\left(-14\right)$
$\frac{3a^2-12b}{3a}$
$\log x+\log\left(x+3\right)=1$
$\log_{13}\left(13\right)+\log_{13}\left(x+2\right)=2$
$3x+4+2x-5$
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