$\frac{\sec x}{\cos\left(x\right)}-\frac{\tan\left(x\right)}{\cot\left(x\right)}=1$
$\left(-10\:-\:2\:.\:4\right)\::\:\left(-\:2\:-\:1\right)\:+\:\left(\:-\:6\:\right)\::\:\left(\:-\:3\:\right)\:-\:\left(\:-\:1\:\right)$
$x=y'\ln\left(y\right)$
$\left(6x+3\right)\cdot\left(x+6\right)$
$\int x\cdot uc$
$a^2+b\:^2=33$
$\frac{d}{dx}\left(3y+\cos\left(y\right)=x^2y\right)$
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