$\frac{1}{secx+1}-\frac{1}{secx-1}$
$3+2\cdot4-\left(-1^2\right)$
$\left(4x^3y^2\right)\left(15x^3y^2\right)$
$\int\frac{1}{x^2-6x+8}dx$
$\left(m-2\right)\left(m+6\right)$
$-4\:+\:6\left(-4x\:+\:3\right)$
$-\:43\:-\:\left(-43\right)\:$
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