$4-\:-81$
$y=\sin^3\:2x^3$
$\frac{16x^8-1}{2x^2-1}$
$\left(x+2y\right)^2-2y\left(x+2y\right)+y^2$
$\int cos\left(2x\right)\cdot\sin^3\left(2x\right)dx$
$2x^2-9x-1$
$8^{0.5}$
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