$6-0.45$
$\int\left(t-6\right)\sin\left(3t+1\right)dt$
$\left(\frac{y^5}{y^2}\right)^2$
$\left(3^{2x}+3^{-2x}\right)^2$
$\frac{6x-2}{2}+\frac{3y-6x}{3}$
$3^2>2^3$
$-x^2+x-6<0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!