$\sqrt[5]{\sqrt[3]{h^4}}$
$\left(4x+3\right)\left(x^2+9\right)$
$p^2+5p+6$
$\left(5-3a^2\right)^3$
$sen2x\cdot cot2x+sen2x=1$
$\left(2-4x\right)\left(-\frac{7}{6x}\right)$
$ydx=xdy$
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