$\left(8^3:4^3\right):\left(6^2:3^2\right)$
$sinx=\frac{tanx}{secx}$
$6x-30+2x$
$\frac{dy}{dx}=\frac{180y}{x}$
$\frac{b}{0.3}=10$
$\frac{4x^4-6x^2+9x+3}{x-2}$
$5x-35+4x+8$
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