$\left(2ab^2-6cd^3\right)\left(2ab^2+3cd^3\right)$
$16x^2-16x+115$
$-3x>12$
$\frac{d}{dx}\left(\frac{\:u}{u^2-1\:}\right)$
$\lim_{x\to\infty}\left(\sqrt{9x^2-12x-3}-3x-1\right)$
$-12\:+\:7\:-\:6\:-\:10\:+\:3\:+\:4\:+\:2$
$16c+2c-8c$
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