$\frac{6+8}{2}+\frac{18}{5+4}$
$\int_1^{\infty}\left(\frac{1}{\sqrt{x^2+1}}\right)dx$
$\frac{x^2+x+1}{x}$
$\left(2x+y-5\right)dx+\left(x+2y-1\right)dy=0$
$2x+2x\le8$
$0.75+0.476+0.9846+0.984$
$-3x+2;x=1$
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