$\frac{a^3}{b^3}-64$
$x-3\ge0$
$\left(2x-6\right)^4$
$x\left(x+1\right)<\:2$
$2^5+5-15+4+\left(-18\right)-8+56-4-21$
$\left(\frac{8}{-2}\right)-3$
$\frac{2x^2-2x+3}{x+1}$
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