$\left(3+2\right)\cdot\sqrt{4}\cdot\left(2+1\right)^2$
$-3^3.-3^1$
$2\left(-3\right)\left(2\right)^2+3\left(-1\right)^4$
$3b^3+2b^3+b^3$
$4x^4+21x^3+7x^2+18x+40$
$\lim_{x\to\infty}\left(\frac{x-1}{x+1}\right)^{2x+1}$
$\log\left(x-3\right)+\log\left(4\right)=\log\left(x\right)$
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