$sin^2\theta\:+\frac{1}{\sqrt{3}}sin\theta\:\:cos\theta\:=0$
$2x^{3\:}+3x^{2\:}-\:18x\:-\:27$
$\frac{x^4-5x^3+20x-16}{x-4}$
$\left(7-\left(-6\right)\right)\cdot\left(-12\right)$
$3m\:-\:5\:=\:10$
$6x+1+7x$
$-7\sin\left(-3x\right)$
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