$y'=-4y+3\cdot\:\:e^{-t}$
$6z^2+3z-18$
$\frac{\sin\left(w\right)}{\csc\left(w\right)}+\frac{\cos\left(w\right)}{\sec\left(w\right)}$
$-4\cdot\left(1+7\right)$
$12+4-16+48-3$
$\left(-2x^2+5x^3\right)\cdot\left(-7x+3\right)$
$\frac{dy}{dx}=ez$
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