$2x^2\cdot ydx=\left(6x^3+y^3\right)dy$

$x\frac{dy}{dx}-\tan\left(y\right)+2x^2\tan\left(y\right)=0$

$\left(\frac{2^3\cdot x}{a^5}\right)$

$x^5\frac{dy}{dx}+y^5=0$

$\left(t-1\right)\left(x-y+z\right)$

$x^2+14x-120$

$7+\left(-2+4-\left(1+3+\left(2+7\right)\right)-4\right)$