$3\:cos^2\theta\:\:+\:cos\:\theta\:=0$
$\int\sqrt{5-u^2}du$
$3\tan^2x\:-\:1\:=0$
$\left(3x^2+9x-3\right)-\left(4x^3-x^2+4x-9\right)$
$\frac{\left(u-2u^2-u^5\right)}{u}$
$\int_{0}^{0}-x^{3}dx$
$\int_2^4\left(\sqrt{1+\left(x-3\right)^2}\right)dx$
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