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Exercise

$\cos\left(4x\right)=8\sin\left(x\right)^2-8\sin\left(x\right)^2+1$

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Final answer to the exercise

$x=0+2\pi n,\:x=\frac{1}{2}\pi+\frac{1}{2}\pi n\:,\:\:n\in\Z$

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