$\frac{1}{\tan^2\left(x\right)}-\frac{\cos^2\left(x\right)}{\tan^2\left(x\right)}=\cos2\left(x\right)$
$9x^2-11x+4$
$\sin\left(bx\right)\sin\left(3x\right)$
$\lim_{x\to0}\left(1-t\left(x\right)\right)$
$\left(10x^2-5x-9\right)-\left(2x^2-5x+7\right)$
$1-\tan^2a\cos^2a=\cos^2a$
$15\cdot7$
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