$=x^5+x^4+4x^3+6x^2+x-7+x^6+2x^4+x^2+5$
$-12-8\cdot6$
$\left(x^3y^3\right)dx+\left(x^3y^2\right)dy=0$
$\left(10\right).\left(+6\right):\left(-12\right)$
$64x^3-125b^3$
$2x^2\le x+4$
$49.\left(-1\right)$
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