$\int x^2\left(3+x\right)^{\frac{3}{2}}dx$

$\frac{d}{dx}\left(3xy-y^3=-4\right)$

$84,5+23,716+164,82-498,79$

$x-40=-15$

$\left(x+2\right)\left(x-2\right)-\left(x+1\right)\left(x-1\right)+\left(x+3\right)\left(x-3\right)$

$6 b ^ { 4 } + 2 b ^ { 4 } - 3 b ^ { 4 } - 2 b ^ { 4 }$

$x^4+2x^2y^2=a^4$