$\frac{18a^4b^{-7}}{6a^{-2}c}$
$4\cos\left(-x\right)\cos\left(8x\right)$
$\lim_{x\to\infty}\left(\left(e^{2x}-5x\right)^{\frac{1}{x}}\right)$
$c-23=-18$
$4x+2$
$1.1\cdot0.1$
$\left(\frac{a}{4}\:-\:2b\right)\left(\frac{a}{4}\:-\:6b\right)$
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