$\int_1^x-\frac{\left(1\right)}{2+t}dt$
$\int\frac{3\cos\left(4x\right)}{\sin^2\left(4x\right)}dx$
$-\frac{2187}{729}\:$
$\left(2+3i\right)\left(4+5i\right)$
$\frac{77.4}{561.4}$
$\left(10a-3b\right)^2$
$\left(w+3\right)\left(4w^2-3w+4\right)$
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