$3x\le2x+12$
$\frac{1}{tan\:a}$
$-\frac{2}{3}y-\frac{1}{6}y$
$\frac { 3 } { 3 } i ^ { 2 }$
$2\int_0^2\sqrt{4+t^2}dt$
$\left(6x\:+\:2\right)\:\left(6x\:+\:4\right)$
$\frac{1}{3^2-9}$
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