$\left(3^2\right)\left(3^8\right)$
$3+99-99$
$3x^2-y+\left(3y^2-x\right)\:\frac{dy}{dx}=0$
$3sin^2x=-9sinx-6$
$10\cdot5+3$
$\left(4x^3+2x\right)$
$-40-\left(1+\left(-44\right)\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!