$\frac{3x+2}{6x-2}+1=\frac{5}{x+1}$

$-x^2+3x-1$

$\lim_{x\to1}\:\:\frac{1}{\sin\left(x\right)}-\frac{x}{\sin\left(x\right)}$

$\left(x-4\right)\left(6x+3\right)$

$\frac{dy}{dx}\left(y=\left(cos\left(x\right)\right)^{5x^3}\right)$

$\frac{\sec\left(x^3+x^2\right)}{\cos\left(x\right)}$

$x^2+0x+16$