$\pi\int_1^5\left(3x+2\right)^2dx$
$5.7=-3u+24.9$
$\left(x+2\right)^3=27$
$y\:-\:1<4$
$sec\left(x\right)-sin\left(x\right)=\frac{1-sin\left(x\right)cos\left(x\right)}{cos\left(x\right)}$
$k^2+11k^230$
$\frac{\tan\left(x\right)}{cot\:\left(x\right)}=tan^2\left(x\right)$
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