$-6x-2=4$
$4m^2n^3\left(-2mn-3m^2n^2-5m^3n^2\right)$
$7+\left(-3\right)+\left(2+3\left(-5\right)\right)$
$\frac{1+\tan y}{1+\cot y}=\tan y$
$10x=140$
$\left(3a-3b\right)-\left(b-c\right)$
$\frac{1}{2}\int1\:+\:tan^2\left(u\right)\:sec\:^2\left(u\right)du$
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