$f\left(x\right)=x^3\left(x-2\right)^2\left(x+3\right)\left(x+5\right)^2$
$\left(3x^2y^4+x^2\right)^3$
$\left(n^3\right)^9$
$\frac{x^3-4x}{x^3+2x^2}$
$\left(\sqrt{\left(b+3y\right)}\cdot\sqrt{8b+y}\right)$
$4x^2-6x-27$
$18\left(m+n\right)$
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