$\sqrt{\sqrt[42]{3.1416}}$
$\left(x+17\right)\left(x+9\right)$
$\left(3x^2-4\right)^4$
$9x^2+30x+10=0$
$\left(\frac{4}{5}x^{2\:}-\:\frac{2}{3}xy\:+\:\frac{5}{2}\right)\left(2x^2\:+\:xy\:-\:1\right)$
$x^3-125a^6$
$\frac{1065.658}{3.6}$
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