$3x-\frac{2}{5}<=x+4$
$10^x-10^{x+3}=999$
$\left(3x^2-6y^3\right)\left(3x^2+6y^3\right)$
$5.25-3$
$\lim_{x\to\infty}\left(2x^3+3x-1\right)$
$\left(-2x-6y+3z\right)+\left(x+5y-8z\right)+\left(x+y-z\right)$
$-256-123$
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