$\int_0^2\left(x^4\cdot\ln\left(x\right)\right)dx$
$\lim_{x\to\infty}\left(\frac{x^5-4x^3}{x^6-x^2-3}\right)$
$\left(6y+40xy^2\right)$
$\lim_{x\to0}\left(\frac{\sin\left(6x\right)}{3x}\right)$
$y=xy+y$
$\lim_{z\to0}\left(ln\left(z\right)\right)$
$-8x^2-20x+48\ge0$
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