$x^2-7x-18\le0$
$\left(5x^2+2\right)\left(5x^2+4\right)$
$16x-56$
$x-7=-13$
$7-3x+2\left(x-7\right)<2x+4$
$\left(x^3\cdot x^{-2}\right)^4$
$+2+\left(+8\right).\left(6\right)-\left(-7+6\right)$
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