$\frac{dy}{dx}\:x^2y-4x^3+16=0$
$f\left(x\right)=3\left(x-4\right)$
$\frac{dy}{dx}=\frac{8xy}{x^2+1}$
$p^2-4$
$\sqrt[7]{1\:}$
$3^5a^7$
$x^2+18x=-40$
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