$\frac{1-\sin^2x}{\cos x\sin x}=\cot x$
$\frac{x}{25}>5$
$9\:+\:16u\:-\:31$
$\int_0^{\pi45}x\:tan^2\:\left(15x\right)dx$
$\ln\left(x+4\right)-\ln\left(x+1\right)=\ln\left(x\right)$
$\left(3x^2y^3\right)\cdot\left(4x^3y^2-5x^2y+3xy\right)$
$9x^2-400$
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