$\int8xe^{-4x}dx$
$\frac{\left(1+cot^2\left(x\right)\right)\left(cos^2\left(x\right)\right)}{cot^2\left(x\right)}=1$
$\left(t^5+2t^3\:\right)^3$
$9b^2-30ab+25a^2$
$8\left(x+2\right)=4x+16$
$5x^2y^2-15zy+20zyz$
$\csc y\:dx\:+\:sec^2\:x\:dy\:=\:0$
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